Adam has some blue stickers and green stickers.
If Adam gives away 27 blue stickers,
the blue stickers will be 10% as many as the green stickers.
If Adam gives away 250 green stickers,
the blue stickers will be 75% as many as the green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 27 |
10 u |
3 p |
4 p + 250 |
Change |
- 27 |
No change |
No change |
- 250 |
After |
1 u |
10 u |
3 p |
4 p |
(a)
10% =
10100 =
110 75% =
75100 =
34 Scenario 1 Number of blue stickers at first = 1 u + 27
Number of green stickers at first = 10 u
Scenario 2 Number of blue stickers at first = 3 p
Number of green stickers at first = 4 p + 250
1 u + 27 = 3 p --- (1)
10 u = 4 p + 250 --- (2)
(1)
x 10 10 u + 270 = 30 p
10 u = 30 p - 270 --- (3)
(3) = (2)
30 p - 270 = 4 p + 250
30 p - 4 p = 270 + 250
26 p = 520
1 p = 520 ÷ 26 = 20
Number of blue stickers
= 3 p
= 3 x 20
= 60
(b)
Number of green stickers at first
= 4 p + 250
= 4 x 20 + 250
= 80 + 250
= 330
Answer(s): (a) 60; (b) 330