Adam has some red stickers and green stickers.
If Adam gives away 28 red stickers,
the red stickers will be 25% as many as the green stickers.
If Adam gives away 9 green stickers,
the red stickers will be 80% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 28 |
4 u |
4 p |
5 p + 9 |
Change |
- 28 |
No change |
No change |
- 9 |
After |
1 u |
4 u |
4 p |
5 p |
(a)
25% =
25100 =
14 80% =
80100 =
45 Scenario 1 Number of red stickers at first = 1 u + 28
Number of green stickers at first = 4 u
Scenario 2 Number of red stickers at first = 4 p
Number of green stickers at first = 5 p + 9
1 u + 28 = 4 p --- (1)
4 u = 5 p + 9 --- (2)
(1)
x 4 4 u + 112 = 16 p
4 u = 16 p - 112 --- (3)
(3) = (2)
16 p - 112 = 5 p + 9
16 p - 5 p = 112 + 9
11 p = 121
1 p = 121 ÷ 11 = 11
Number of red stickers
= 4 p
= 4 x 11
= 44
(b)
Number of green stickers at first
= 5 p + 9
= 5 x 11 + 9
= 55 + 9
= 64
Answer(s): (a) 44; (b) 64