Adam has some green stickers and red stickers.
If Adam gives away 28 green stickers,
the green stickers will be 25% as many as the red stickers.
If Adam gives away 152 red stickers,
the green stickers will be 80% as many as the red stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u + 28 |
4 u |
4 p |
5 p + 152 |
Change |
- 28 |
No change |
No change |
- 152 |
After |
1 u |
4 u |
4 p |
5 p |
(a)
25% =
25100 =
14 80% =
80100 =
45 Scenario 1 Number of green stickers at first = 1 u + 28
Number of red stickers at first = 4 u
Scenario 2 Number of green stickers at first = 4 p
Number of red stickers at first = 5 p + 152
1 u + 28 = 4 p --- (1)
4 u = 5 p + 152 --- (2)
(1)
x 4 4 u + 112 = 16 p
4 u = 16 p - 112 --- (3)
(3) = (2)
16 p - 112 = 5 p + 152
16 p - 5 p = 112 + 152
11 p = 264
1 p = 264 ÷ 11 = 24
Number of green stickers
= 4 p
= 4 x 24
= 96
(b)
Number of red stickers at first
= 5 p + 152
= 5 x 24 + 152
= 120 + 152
= 272
Answer(s): (a) 96; (b) 272