Adam has some blue stickers and red stickers.
If Adam gives away 42 blue stickers,
the blue stickers will be 10% as many as the red stickers.
If Adam gives away 595 red stickers,
the blue stickers will be 80% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Red |
Blue |
Red |
Before |
1 u + 42 |
10 u |
4 p |
5 p + 595 |
Change |
- 42 |
No change |
No change |
- 595 |
After |
1 u |
10 u |
4 p |
5 p |
(a)
10% =
10100 =
110 80% =
80100 =
45 Scenario 1 Number of blue stickers at first = 1 u + 42
Number of red stickers at first = 10 u
Scenario 2 Number of blue stickers at first = 4 p
Number of red stickers at first = 5 p + 595
1 u + 42 = 4 p --- (1)
10 u = 5 p + 595 --- (2)
(1)
x 10 10 u + 420 = 40 p
10 u = 40 p - 420 --- (3)
(3) = (2)
40 p - 420 = 5 p + 595
40 p - 5 p = 420 + 595
35 p = 1015
1 p = 1015 ÷ 35 = 29
Number of blue stickers
= 4 p
= 4 x 29
= 116
(b)
Number of red stickers at first
= 5 p + 595
= 5 x 29 + 595
= 145 + 595
= 740
Answer(s): (a) 116; (b) 740