Adam has some red stickers and green stickers.
If Adam gives away 13 red stickers,
the red stickers will be 10% as many as the green stickers.
If Adam gives away 234 green stickers,
the red stickers will be 75% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 13 |
10 u |
3 p |
4 p + 234 |
Change |
- 13 |
No change |
No change |
- 234 |
After |
1 u |
10 u |
3 p |
4 p |
(a)
10% =
10100 =
110 75% =
75100 =
34 Scenario 1 Number of red stickers at first = 1 u + 13
Number of green stickers at first = 10 u
Scenario 2 Number of red stickers at first = 3 p
Number of green stickers at first = 4 p + 234
1 u + 13 = 3 p --- (1)
10 u = 4 p + 234 --- (2)
(1)
x 10 10 u + 130 = 30 p
10 u = 30 p - 130 --- (3)
(3) = (2)
30 p - 130 = 4 p + 234
30 p - 4 p = 130 + 234
26 p = 364
1 p = 364 ÷ 26 = 14
Number of red stickers
= 3 p
= 3 x 14
= 42
(b)
Number of green stickers at first
= 4 p + 234
= 4 x 14 + 234
= 56 + 234
= 290
Answer(s): (a) 42; (b) 290