Adam has some red stickers and blue stickers.
If Adam gives away 37 red stickers,
the red stickers will be 25% as many as the blue stickers.
If Adam gives away 28 blue stickers,
the red stickers will be 75% as many as the blue stickers.
- How many red stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Blue |
Red |
Blue |
Before |
1 u + 37 |
4 u |
3 p |
4 p + 28 |
Change |
- 37 |
No change |
No change |
- 28 |
After |
1 u |
4 u |
3 p |
4 p |
(a)
25% =
25100 =
14 75% =
75100 =
34 Scenario 1 Number of red stickers at first = 1 u + 37
Number of blue stickers at first = 4 u
Scenario 2 Number of red stickers at first = 3 p
Number of blue stickers at first = 4 p + 28
1 u + 37 = 3 p --- (1)
4 u = 4 p + 28 --- (2)
(1)
x 4 4 u + 148 = 12 p
4 u = 12 p - 148 --- (3)
(3) = (2)
12 p - 148 = 4 p + 28
12 p - 4 p = 148 + 28
8 p = 176
1 p = 176 ÷ 8 = 22
Number of red stickers
= 3 p
= 3 x 22
= 66
(b)
Number of blue stickers at first
= 4 p + 28
= 4 x 22 + 28
= 88 + 28
= 116
Answer(s): (a) 66; (b) 116