Adam has some red stickers and green stickers.
If Adam gives away 19 red stickers,
the red stickers will be 20% as many as the green stickers.
If Adam gives away 48 green stickers,
the red stickers will be 75% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 19 |
5 u |
3 p |
4 p + 48 |
Change |
- 19 |
No change |
No change |
- 48 |
After |
1 u |
5 u |
3 p |
4 p |
(a)
20% =
20100 =
15 75% =
75100 =
34 Scenario 1 Number of red stickers at first = 1 u + 19
Number of green stickers at first = 5 u
Scenario 2 Number of red stickers at first = 3 p
Number of green stickers at first = 4 p + 48
1 u + 19 = 3 p --- (1)
5 u = 4 p + 48 --- (2)
(1)
x 5 5 u + 95 = 15 p
5 u = 15 p - 95 --- (3)
(3) = (2)
15 p - 95 = 4 p + 48
15 p - 4 p = 95 + 48
11 p = 143
1 p = 143 ÷ 11 = 13
Number of red stickers
= 3 p
= 3 x 13
= 39
(b)
Number of green stickers at first
= 4 p + 48
= 4 x 13 + 48
= 52 + 48
= 100
Answer(s): (a) 39; (b) 100