Adam has some green stickers and red stickers.
If Adam gives away 34 green stickers,
the green stickers will be 10% as many as the red stickers.
If Adam gives away 50 red stickers,
the green stickers will be 75% as many as the red stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u + 34 |
10 u |
3 p |
4 p + 50 |
Change |
- 34 |
No change |
No change |
- 50 |
After |
1 u |
10 u |
3 p |
4 p |
(a)
10% =
10100 =
110 75% =
75100 =
34 Scenario 1 Number of green stickers at first = 1 u + 34
Number of red stickers at first = 10 u
Scenario 2 Number of green stickers at first = 3 p
Number of red stickers at first = 4 p + 50
1 u + 34 = 3 p --- (1)
10 u = 4 p + 50 --- (2)
(1)
x 10 10 u + 340 = 30 p
10 u = 30 p - 340 --- (3)
(3) = (2)
30 p - 340 = 4 p + 50
30 p - 4 p = 340 + 50
26 p = 390
1 p = 390 ÷ 26 = 15
Number of green stickers
= 3 p
= 3 x 15
= 45
(b)
Number of red stickers at first
= 4 p + 50
= 4 x 15 + 50
= 60 + 50
= 110
Answer(s): (a) 45; (b) 110