Adam has some green stickers and blue stickers.
If Adam gives away 18 green stickers,
the green stickers will be 20% as many as the blue stickers.
If Adam gives away 50 blue stickers,
the green stickers will be 40% as many as the blue stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 18 |
5 u |
2 p |
5 p + 50 |
Change |
- 18 |
No change |
No change |
- 50 |
After |
1 u |
5 u |
2 p |
5 p |
(a)
20% =
20100 =
15 40% =
40100 =
25 Scenario 1 Number of green stickers at first = 1 u + 18
Number of blue stickers at first = 5 u
Scenario 2 Number of green stickers at first = 2 p
Number of blue stickers at first = 5 p + 50
1 u + 18 = 2 p --- (1)
5 u = 5 p + 50 --- (2)
(1)
x 5 5 u + 90 = 10 p
5 u = 10 p - 90 --- (3)
(3) = (2)
10 p - 90 = 5 p + 50
10 p - 5 p = 90 + 50
5 p = 140
1 p = 140 ÷ 5 = 28
Number of green stickers
= 2 p
= 2 x 28
= 56
(b)
Number of blue stickers at first
= 5 p + 50
= 5 x 28 + 50
= 140 + 50
= 190
Answer(s): (a) 56; (b) 190