Adam has some green stickers and red stickers.
If Adam gives away 14 green stickers,
the green stickers will be 20% as many as the red stickers.
If Adam gives away 216 red stickers,
the green stickers will be 75% as many as the red stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u + 14 |
5 u |
3 p |
4 p + 216 |
Change |
- 14 |
No change |
No change |
- 216 |
After |
1 u |
5 u |
3 p |
4 p |
(a)
20% =
20100 =
15 75% =
75100 =
34 Scenario 1 Number of green stickers at first = 1 u + 14
Number of red stickers at first = 5 u
Scenario 2 Number of green stickers at first = 3 p
Number of red stickers at first = 4 p + 216
1 u + 14 = 3 p --- (1)
5 u = 4 p + 216 --- (2)
(1)
x 5 5 u + 70 = 15 p
5 u = 15 p - 70 --- (3)
(3) = (2)
15 p - 70 = 4 p + 216
15 p - 4 p = 70 + 216
11 p = 286
1 p = 286 ÷ 11 = 26
Number of green stickers
= 3 p
= 3 x 26
= 78
(b)
Number of red stickers at first
= 4 p + 216
= 4 x 26 + 216
= 104 + 216
= 320
Answer(s): (a) 78; (b) 320