Adam has some green stickers and red stickers.
If Adam gives away 28 green stickers,
the green stickers will be 20% as many as the red stickers.
If Adam gives away 10 red stickers,
the green stickers will be 80% as many as the red stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u + 28 |
5 u |
4 p |
5 p + 10 |
Change |
- 28 |
No change |
No change |
- 10 |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of green stickers at first = 1 u + 28
Number of red stickers at first = 5 u
Scenario 2 Number of green stickers at first = 4 p
Number of red stickers at first = 5 p + 10
1 u + 28 = 4 p --- (1)
5 u = 5 p + 10 --- (2)
(1)
x 5 5 u + 140 = 20 p
5 u = 20 p - 140 --- (3)
(3) = (2)
20 p - 140 = 5 p + 10
20 p - 5 p = 140 + 10
15 p = 150
1 p = 150 ÷ 15 = 10
Number of green stickers
= 4 p
= 4 x 10
= 40
(b)
Number of red stickers at first
= 5 p + 10
= 5 x 10 + 10
= 50 + 10
= 60
Answer(s): (a) 40; (b) 60