Adam has some blue stickers and green stickers.
If Adam gives away 23 blue stickers,
the blue stickers will be 20% as many as the green stickers.
If Adam gives away 65 green stickers,
the blue stickers will be 80% as many as the green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 23 |
5 u |
4 p |
5 p + 65 |
Change |
- 23 |
No change |
No change |
- 65 |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of blue stickers at first = 1 u + 23
Number of green stickers at first = 5 u
Scenario 2 Number of blue stickers at first = 4 p
Number of green stickers at first = 5 p + 65
1 u + 23 = 4 p --- (1)
5 u = 5 p + 65 --- (2)
(1)
x 5 5 u + 115 = 20 p
5 u = 20 p - 115 --- (3)
(3) = (2)
20 p - 115 = 5 p + 65
20 p - 5 p = 115 + 65
15 p = 180
1 p = 180 ÷ 15 = 12
Number of blue stickers
= 4 p
= 4 x 12
= 48
(b)
Number of green stickers at first
= 5 p + 65
= 5 x 12 + 65
= 60 + 65
= 125
Answer(s): (a) 48; (b) 125