Adam has some red stickers and green stickers.
If Adam gives away 14 red stickers,
the red stickers will be 25% as many as the green stickers.
If Adam gives away 142 green stickers,
the red stickers will be 80% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 14 |
4 u |
4 p |
5 p + 142 |
Change |
- 14 |
No change |
No change |
- 142 |
After |
1 u |
4 u |
4 p |
5 p |
(a)
25% =
25100 =
14 80% =
80100 =
45 Scenario 1 Number of red stickers at first = 1 u + 14
Number of green stickers at first = 4 u
Scenario 2 Number of red stickers at first = 4 p
Number of green stickers at first = 5 p + 142
1 u + 14 = 4 p --- (1)
4 u = 5 p + 142 --- (2)
(1)
x 4 4 u + 56 = 16 p
4 u = 16 p - 56 --- (3)
(3) = (2)
16 p - 56 = 5 p + 142
16 p - 5 p = 56 + 142
11 p = 198
1 p = 198 ÷ 11 = 18
Number of red stickers
= 4 p
= 4 x 18
= 72
(b)
Number of green stickers at first
= 5 p + 142
= 5 x 18 + 142
= 90 + 142
= 232
Answer(s): (a) 72; (b) 232