Adam has some blue stickers and green stickers.
If Adam gives away 43 blue stickers,
the blue stickers will be 20% as many as the green stickers.
If Adam gives away 49 green stickers,
the blue stickers will be 75% as many as the green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 43 |
5 u |
3 p |
4 p + 49 |
Change |
- 43 |
No change |
No change |
- 49 |
After |
1 u |
5 u |
3 p |
4 p |
(a)
20% =
20100 =
15 75% =
75100 =
34 Scenario 1 Number of blue stickers at first = 1 u + 43
Number of green stickers at first = 5 u
Scenario 2 Number of blue stickers at first = 3 p
Number of green stickers at first = 4 p + 49
1 u + 43 = 3 p --- (1)
5 u = 4 p + 49 --- (2)
(1)
x 5 5 u + 215 = 15 p
5 u = 15 p - 215 --- (3)
(3) = (2)
15 p - 215 = 4 p + 49
15 p - 4 p = 215 + 49
11 p = 264
1 p = 264 ÷ 11 = 24
Number of blue stickers
= 3 p
= 3 x 24
= 72
(b)
Number of green stickers at first
= 4 p + 49
= 4 x 24 + 49
= 96 + 49
= 145
Answer(s): (a) 72; (b) 145