Adam has some green stickers and blue stickers.
If Adam gives away 16 green stickers,
the green stickers will be 10% as many as the blue stickers.
If Adam gives away 152 blue stickers,
the green stickers will be 75% as many as the blue stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 16 |
10 u |
3 p |
4 p + 152 |
Change |
- 16 |
No change |
No change |
- 152 |
After |
1 u |
10 u |
3 p |
4 p |
(a)
10% =
10100 =
110 75% =
75100 =
34 Scenario 1 Number of green stickers at first = 1 u + 16
Number of blue stickers at first = 10 u
Scenario 2 Number of green stickers at first = 3 p
Number of blue stickers at first = 4 p + 152
1 u + 16 = 3 p --- (1)
10 u = 4 p + 152 --- (2)
(1)
x 10 10 u + 160 = 30 p
10 u = 30 p - 160 --- (3)
(3) = (2)
30 p - 160 = 4 p + 152
30 p - 4 p = 160 + 152
26 p = 312
1 p = 312 ÷ 26 = 12
Number of green stickers
= 3 p
= 3 x 12
= 36
(b)
Number of blue stickers at first
= 4 p + 152
= 4 x 12 + 152
= 48 + 152
= 200
Answer(s): (a) 36; (b) 200