Adam has some blue stickers and red stickers.
If Adam receives another 58 blue stickers,
the blue stickers will be 50% as many as the red stickers.
If Adam gives away 61 red stickers,
the blue stickers will be 40% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u - 58 |
2 u |
2 p |
5 p + 61 |
Change |
+ 58 |
No change |
No change |
- 61 |
After |
1 u |
2 u |
2 p |
5 p |
(a)
50% =
50100 =
12 40% =
40100 =
25 Scenario 1 Number of red stickers at first = 1 u - 58
Number of green stickers at first = 2 u
Scenario 2 Number of red stickers at first = 2 p
Number of green stickers at first = 5 p + 61
1 u - 58 = 2 p --- (1)
2 u = 5 p + 61 --- (2)
From (1)1 u = 58 + 2 p --- (3) (3) x 22 u = 116 + 4 p --- (4)
(2) = (4)5 p + 61 = 116 + 4 p5 p - 4 p = 116 - 611 p = 55
Number of red stickers = 2 p = 2 x 55 = 110 (b) Number of green stickers = 5 p + 61 = 5 x 55 + 61
= 275 + 61= 336 Answer(s): (a) 110; (b) 336