Adam has some blue stickers and red stickers.
If Adam receives another 52 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 544 red stickers,
the blue stickers will be 60% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Blue |
Red |
Blue |
Before |
1 u - 52 |
4 u |
3 p |
5 p + 544 |
Change |
+ 52 |
No change |
No change |
- 544 |
After |
1 u |
4 u |
3 p |
5 p |
(a)
25% =
25100 =
14 60% =
60100 =
35 Scenario 1 Number of red stickers at first = 1 u - 52
Number of blue stickers at first = 4 u
Scenario 2 Number of red stickers at first = 3 p
Number of blue stickers at first = 5 p + 544
1 u - 52 = 3 p --- (1)
4 u = 5 p + 544 --- (2)
From (1)1 u = 52 + 3 p --- (3) (3) x 44 u = 208 + 12 p --- (4)
(4) = (2)208 + 12 p = 5 p + 544 12 p - 5 p = 544 - 2087 p = 336
1 p = 336 ÷ 7 = 48
Number of blue stickers = 3 p = 3 x 48 = 144 (b) Number of red stickers = 5 p + 544 = 5 x 48 + 544
= 240 + 544= 784 Answer(s): (a) 144; (b) 784