Adam has some blue stickers and red stickers.
If Adam receives another 58 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 608 red stickers,
the blue stickers will be 75% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Red |
Blue |
Red |
Before |
1 u - 58 |
4 u |
3 p |
4 p + 608 |
Change |
+ 58 |
No change |
No change |
- 608 |
After |
1 u |
4 u |
3 p |
4 p |
(a)
25% =
25100 =
14 75% =
75100 =
34 Scenario 1 Number of blue stickers at first = 1 u - 58
Number of red stickers at first = 4 u
Scenario 2 Number of blue stickers at first = 3 p
Number of red stickers at first = 4 p + 608
1 u - 58 = 3 p --- (1)
4 u = 4 p + 608 --- (2)
From (1)1 u = 58 + 3 p --- (3) (3) x 44 u = 232 + 12 p --- (4)
(4) = (2)232 + 12 p = 4 p + 608 12 p - 4 p = 608 - 2328 p = 376
1 p = 376 ÷ 8 = 47
Number of blue stickers = 3 p = 3 x 47 = 141 (b) Number of red stickers = 4 p + 608 = 4 x 47 + 608
= 188 + 608= 796 Answer(s): (a) 141; (b) 796