Adam has some blue stickers and red stickers.
If Adam receives another 67 blue stickers,
the blue stickers will be 50% as many as the red stickers.
If Adam gives away 20 red stickers,
the blue stickers will be 40% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u - 67 |
2 u |
2 p |
5 p + 20 |
Change |
+ 67 |
No change |
No change |
- 20 |
After |
1 u |
2 u |
2 p |
5 p |
(a)
50% =
50100 =
12 40% =
40100 =
25 Scenario 1 Number of green stickers at first = 1 u - 67
Number of blue stickers at first = 2 u
Scenario 2 Number of green stickers at first = 2 p
Number of blue stickers at first = 5 p + 20
1 u - 67 = 2 p --- (1)
2 u = 5 p + 20 --- (2)
From (1)1 u = 67 + 2 p --- (3) (3) x 22 u = 134 + 4 p --- (4)
(2) = (4)5 p + 20 = 134 + 4 p5 p - 4 p = 134 - 201 p = 114
Number of green stickers = 2 p = 2 x 114 = 228 (b) Number of blue stickers = 5 p + 20 = 5 x 114 + 20
= 570 + 20= 590 Answer(s): (a) 228; (b) 590