Adam has some blue stickers and red stickers.
If Adam receives another 76 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 521 red stickers,
the blue stickers will be 60% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u - 76 |
4 u |
3 p |
5 p + 521 |
Change |
+ 76 |
No change |
No change |
- 521 |
After |
1 u |
4 u |
3 p |
5 p |
(a)
25% =
25100 =
14 60% =
60100 =
35 Scenario 1 Number of red stickers at first = 1 u - 76
Number of green stickers at first = 4 u
Scenario 2 Number of red stickers at first = 3 p
Number of green stickers at first = 5 p + 521
1 u - 76 = 3 p --- (1)
4 u = 5 p + 521 --- (2)
From (1)1 u = 76 + 3 p --- (3) (3) x 44 u = 304 + 12 p --- (4)
(4) = (2)304 + 12 p = 5 p + 521 12 p - 5 p = 521 - 3047 p = 217
1 p = 217 ÷ 7 = 31
Number of blue stickers = 3 p = 3 x 31 = 93 (b) Number of red stickers = 5 p + 521 = 5 x 31 + 521
= 155 + 521= 676 Answer(s): (a) 93; (b) 676