Adam has some blue stickers and red stickers.
If Adam receives another 96 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 510 red stickers,
the blue stickers will be 60% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u - 96 |
4 u |
3 p |
5 p + 510 |
Change |
+ 96 |
No change |
No change |
- 510 |
After |
1 u |
4 u |
3 p |
5 p |
(a)
25% =
25100 =
14 60% =
60100 =
35 Scenario 1 Number of green stickers at first = 1 u - 96
Number of blue stickers at first = 4 u
Scenario 2 Number of green stickers at first = 3 p
Number of blue stickers at first = 5 p + 510
1 u - 96 = 3 p --- (1)
4 u = 5 p + 510 --- (2)
From (1)1 u = 96 + 3 p --- (3) (3) x 44 u = 384 + 12 p --- (4)
(4) = (2)384 + 12 p = 5 p + 510 12 p - 5 p = 510 - 3847 p = 126
1 p = 126 ÷ 7 = 18
Number of blue stickers = 3 p = 3 x 18 = 54 (b) Number of red stickers = 5 p + 510 = 5 x 18 + 510
= 90 + 510= 600 Answer(s): (a) 54; (b) 600