Adam has some blue stickers and red stickers.
If Adam receives another 57 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 444 red stickers,
the blue stickers will be 75% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u - 57 |
4 u |
3 p |
4 p + 444 |
Change |
+ 57 |
No change |
No change |
- 444 |
After |
1 u |
4 u |
3 p |
4 p |
(a)
25% =
25100 =
14 75% =
75100 =
34 Scenario 1 Number of green stickers at first = 1 u - 57
Number of red stickers at first = 4 u
Scenario 2 Number of green stickers at first = 3 p
Number of red stickers at first = 4 p + 444
1 u - 57 = 3 p --- (1)
4 u = 4 p + 444 --- (2)
From (1)1 u = 57 + 3 p --- (3) (3) x 44 u = 228 + 12 p --- (4)
(4) = (2)228 + 12 p = 4 p + 444 12 p - 4 p = 444 - 2288 p = 216
1 p = 216 ÷ 8 = 27
Number of blue stickers = 3 p = 3 x 27 = 81 (b) Number of red stickers = 4 p + 444 = 4 x 27 + 444
= 108 + 444= 552 Answer(s): (a) 81; (b) 552