Adam has some blue stickers and red stickers.
If Adam receives another 51 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 484 red stickers,
the blue stickers will be 60% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u - 51 |
4 u |
3 p |
5 p + 484 |
Change |
+ 51 |
No change |
No change |
- 484 |
After |
1 u |
4 u |
3 p |
5 p |
(a)
25% =
25100 =
14 60% =
60100 =
35 Scenario 1 Number of green stickers at first = 1 u - 51
Number of red stickers at first = 4 u
Scenario 2 Number of green stickers at first = 3 p
Number of red stickers at first = 5 p + 484
1 u - 51 = 3 p --- (1)
4 u = 5 p + 484 --- (2)
From (1)1 u = 51 + 3 p --- (3) (3) x 44 u = 204 + 12 p --- (4)
(4) = (2)204 + 12 p = 5 p + 484 12 p - 5 p = 484 - 2047 p = 280
1 p = 280 ÷ 7 = 40
Number of blue stickers = 3 p = 3 x 40 = 120 (b) Number of red stickers = 5 p + 484 = 5 x 40 + 484
= 200 + 484= 684 Answer(s): (a) 120; (b) 684