Adam has some blue stickers and red stickers.
If Adam receives another 52 blue stickers,
the blue stickers will be 50% as many as the red stickers.
If Adam gives away 84 red stickers,
the blue stickers will be 40% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u - 52 |
2 u |
2 p |
5 p + 84 |
Change |
+ 52 |
No change |
No change |
- 84 |
After |
1 u |
2 u |
2 p |
5 p |
(a)
50% =
50100 =
12 40% =
40100 =
25 Scenario 1 Number of green stickers at first = 1 u - 52
Number of red stickers at first = 2 u
Scenario 2 Number of green stickers at first = 2 p
Number of red stickers at first = 5 p + 84
1 u - 52 = 2 p --- (1)
2 u = 5 p + 84 --- (2)
From (1)1 u = 52 + 2 p --- (3) (3) x 22 u = 104 + 4 p --- (4)
(2) = (4)5 p + 84 = 104 + 4 p5 p - 4 p = 104 - 841 p = 20
Number of green stickers = 2 p = 2 x 20 = 40 (b) Number of red stickers = 5 p + 84 = 5 x 20 + 84
= 100 + 84= 184 Answer(s): (a) 40; (b) 184