Adam has some blue stickers and red stickers.
If Adam receives another 43 blue stickers,
the blue stickers will be 50% as many as the red stickers.
If Adam gives away 62 red stickers,
the blue stickers will be 40% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u - 43 |
2 u |
2 p |
5 p + 62 |
Change |
+ 43 |
No change |
No change |
- 62 |
After |
1 u |
2 u |
2 p |
5 p |
(a)
50% =
50100 =
12 40% =
40100 =
25 Scenario 1 Number of blue stickers at first = 1 u - 43
Number of green stickers at first = 2 u
Scenario 2 Number of blue stickers at first = 2 p
Number of green stickers at first = 5 p + 62
1 u - 43 = 2 p --- (1)
2 u = 5 p + 62 --- (2)
From (1)1 u = 43 + 2 p --- (3) (3) x 22 u = 86 + 4 p --- (4)
(2) = (4)5 p + 62 = 86 + 4 p5 p - 4 p = 86 - 621 p = 24
Number of blue stickers = 2 p = 2 x 24 = 48 (b) Number of green stickers = 5 p + 62 = 5 x 24 + 62
= 120 + 62= 182 Answer(s): (a) 48; (b) 182