Adam has some blue stickers and red stickers.
If Adam receives another 42 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 560 red stickers,
the blue stickers will be 75% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u - 42 |
4 u |
3 p |
4 p + 560 |
Change |
+ 42 |
No change |
No change |
- 560 |
After |
1 u |
4 u |
3 p |
4 p |
(a)
25% =
25100 =
14 75% =
75100 =
34 Scenario 1 Number of green stickers at first = 1 u - 42
Number of blue stickers at first = 4 u
Scenario 2 Number of green stickers at first = 3 p
Number of blue stickers at first = 4 p + 560
1 u - 42 = 3 p --- (1)
4 u = 4 p + 560 --- (2)
From (1)1 u = 42 + 3 p --- (3) (3) x 44 u = 168 + 12 p --- (4)
(4) = (2)168 + 12 p = 4 p + 560 12 p - 4 p = 560 - 1688 p = 392
1 p = 392 ÷ 8 = 49
Number of blue stickers = 3 p = 3 x 49 = 147 (b) Number of red stickers = 4 p + 560 = 4 x 49 + 560
= 196 + 560= 756 Answer(s): (a) 147; (b) 756