Adam has some blue stickers and red stickers.
If Adam receives another 43 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 468 red stickers,
the blue stickers will be 75% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u - 43 |
4 u |
3 p |
4 p + 468 |
Change |
+ 43 |
No change |
No change |
- 468 |
After |
1 u |
4 u |
3 p |
4 p |
(a)
25% =
25100 =
14 75% =
75100 =
34 Scenario 1 Number of red stickers at first = 1 u - 43
Number of green stickers at first = 4 u
Scenario 2 Number of red stickers at first = 3 p
Number of green stickers at first = 4 p + 468
1 u - 43 = 3 p --- (1)
4 u = 4 p + 468 --- (2)
From (1)1 u = 43 + 3 p --- (3) (3) x 44 u = 172 + 12 p --- (4)
(4) = (2)172 + 12 p = 4 p + 468 12 p - 4 p = 468 - 1728 p = 296
1 p = 296 ÷ 8 = 37
Number of blue stickers = 3 p = 3 x 37 = 111 (b) Number of red stickers = 4 p + 468 = 4 x 37 + 468
= 148 + 468= 616 Answer(s): (a) 111; (b) 616