Adam has some blue stickers and red stickers.
If Adam receives another 54 blue stickers,
the blue stickers will be 50% as many as the red stickers.
If Adam gives away 55 red stickers,
the blue stickers will be 40% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u - 54 |
2 u |
2 p |
5 p + 55 |
Change |
+ 54 |
No change |
No change |
- 55 |
After |
1 u |
2 u |
2 p |
5 p |
(a)
50% =
50100 =
12 40% =
40100 =
25 Scenario 1 Number of blue stickers at first = 1 u - 54
Number of green stickers at first = 2 u
Scenario 2 Number of blue stickers at first = 2 p
Number of green stickers at first = 5 p + 55
1 u - 54 = 2 p --- (1)
2 u = 5 p + 55 --- (2)
From (1)1 u = 54 + 2 p --- (3) (3) x 22 u = 108 + 4 p --- (4)
(2) = (4)5 p + 55 = 108 + 4 p5 p - 4 p = 108 - 551 p = 53
Number of blue stickers = 2 p = 2 x 53 = 106 (b) Number of green stickers = 5 p + 55 = 5 x 53 + 55
= 265 + 55= 320 Answer(s): (a) 106; (b) 320