Adam has some blue stickers and red stickers.
If Adam receives another 70 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 560 red stickers,
the blue stickers will be 60% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u - 70 |
4 u |
3 p |
5 p + 560 |
Change |
+ 70 |
No change |
No change |
- 560 |
After |
1 u |
4 u |
3 p |
5 p |
(a)
25% =
25100 =
14 60% =
60100 =
35 Scenario 1 Number of blue stickers at first = 1 u - 70
Number of green stickers at first = 4 u
Scenario 2 Number of blue stickers at first = 3 p
Number of green stickers at first = 5 p + 560
1 u - 70 = 3 p --- (1)
4 u = 5 p + 560 --- (2)
From (1)1 u = 70 + 3 p --- (3) (3) x 44 u = 280 + 12 p --- (4)
(4) = (2)280 + 12 p = 5 p + 560 12 p - 5 p = 560 - 2807 p = 280
1 p = 280 ÷ 7 = 40
Number of blue stickers = 3 p = 3 x 40 = 120 (b) Number of red stickers = 5 p + 560 = 5 x 40 + 560
= 200 + 560= 760 Answer(s): (a) 120; (b) 760