Adam has some green stickers and blue stickers.
If 250 green stickers are added, 40% of the stickers will be blue stickers.
If 150 blue stickers are added, 10% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
3 u - 250 |
2 u |
1 p |
9 p - 150 |
Change |
+ 250 |
No change |
No change |
+ 150 |
After |
3 u |
2 u |
1 p |
9 p |
(a)
40% =
40100 =
25 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are green
= 1 -
25 =
35 Number of green stickers at first = 3 u - 250
Number of blue stickers at first = 2 u
Scenario 2 Fraction of the stickers that are blue
= 1 -
110=
910 Number of green stickers at first = 1 p
Number of blue stickers at first = 9 p - 150
3 u - 250 = 1 p --- (1)
2 u = 9 p - 150
2 u + 150 = 9 p --- (2)
(1)
x 9 27 u - 2250 = 9 p --- (3)
(3) = (2)
27 u - 2250 = 2 u + 150
27 u - 2 u = 2250 + 150
25 u = 2400
1 u = 2400 ÷ 25 = 96
Number of green stickers
= 3 u - 250
= 3 x 96 - 250
= 288 - 250
= 38
(b)
Number of blue stickers
= 2 u
= 2 x 96
= 192
Answer(s): (a) 38; (b) 192