Adam has some green stickers and blue stickers.
If 280 green stickers are added, 30% of the stickers will be blue stickers.
If 366 blue stickers are added, 25% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
7 u - 280 |
3 u |
1 p |
3 p - 366 |
Change |
+ 280 |
No change |
No change |
+ 366 |
After |
7 u |
3 u |
1 p |
3 p |
(a)
30% =
30100 =
310 25% =
25100 =
14 Scenario 1 Fraction of the stickers that are green
= 1 -
310 =
710 Number of green stickers at first = 7 u - 280
Number of blue stickers at first = 3 u
Scenario 2 Fraction of the stickers that are blue
= 1 -
14=
34 Number of green stickers at first = 1 p
Number of blue stickers at first = 3 p - 366
7 u - 280 = 1 p --- (1)
3 u = 3 p - 366
3 u + 366 = 3 p --- (2)
(1)
x 3 21 u - 840 = 3 p --- (3)
(3) = (2)
21 u - 840 = 3 u + 366
21 u - 3 u = 840 + 366
18 u = 1206
1 u = 1206 ÷ 18 = 67
Number of green stickers
= 7 u - 280
= 7 x 67 - 280
= 469 - 280
= 189
(b)
Number of blue stickers
= 3 u
= 3 x 67
= 201
Answer(s): (a) 189; (b) 201