Adam has some green stickers and red stickers.
If 383 green stickers are added, 30% of the stickers will be red stickers.
If 273 red stickers are added, 25% of the stickers will be green stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
7 u - 383 |
3 u |
1 p |
3 p - 273 |
Change |
+ 383 |
No change |
No change |
+ 273 |
After |
7 u |
3 u |
1 p |
3 p |
(a)
30% =
30100 =
310 25% =
25100 =
14 Scenario 1 Fraction of the stickers that are green
= 1 -
310 =
710 Number of green stickers at first = 7 u - 383
Number of red stickers at first = 3 u
Scenario 2 Fraction of the stickers that are red
= 1 -
14=
34 Number of green stickers at first = 1 p
Number of red stickers at first = 3 p - 273
7 u - 383 = 1 p --- (1)
3 u = 3 p - 273
3 u + 273 = 3 p --- (2)
(1)
x 3 21 u - 1149 = 3 p --- (3)
(3) = (2)
21 u - 1149 = 3 u + 273
21 u - 3 u = 1149 + 273
18 u = 1422
1 u = 1422 ÷ 18 = 79
Number of green stickers
= 7 u - 383
= 7 x 79 - 383
= 553 - 383
= 170
(b)
Number of red stickers
= 3 u
= 3 x 79
= 237
Answer(s): (a) 170; (b) 237