Adam has some green stickers and blue stickers.
If 362 green stickers are added, 30% of the stickers will be blue stickers.
If 156 blue stickers are added, 25% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
7 u - 362 |
3 u |
1 p |
3 p - 156 |
Change |
+ 362 |
No change |
No change |
+ 156 |
After |
7 u |
3 u |
1 p |
3 p |
(a)
30% =
30100 =
310 25% =
25100 =
14 Scenario 1 Fraction of the stickers that are green
= 1 -
310 =
710 Number of green stickers at first = 7 u - 362
Number of blue stickers at first = 3 u
Scenario 2 Fraction of the stickers that are blue
= 1 -
14=
34 Number of green stickers at first = 1 p
Number of blue stickers at first = 3 p - 156
7 u - 362 = 1 p --- (1)
3 u = 3 p - 156
3 u + 156 = 3 p --- (2)
(1)
x 3 21 u - 1086 = 3 p --- (3)
(3) = (2)
21 u - 1086 = 3 u + 156
21 u - 3 u = 1086 + 156
18 u = 1242
1 u = 1242 ÷ 18 = 69
Number of green stickers
= 7 u - 362
= 7 x 69 - 362
= 483 - 362
= 121
(b)
Number of blue stickers
= 3 u
= 3 x 69
= 207
Answer(s): (a) 121; (b) 207