Adam has some green stickers and blue stickers.
If 348 green stickers are added, 40% of the stickers will be blue stickers.
If 258 blue stickers are added, 20% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
3 u - 348 |
2 u |
1 p |
4 p - 258 |
Change |
+ 348 |
No change |
No change |
+ 258 |
After |
3 u |
2 u |
1 p |
4 p |
(a)
40% =
40100 =
25 20% =
20100 =
15 Scenario 1 Fraction of the stickers that are green
= 1 -
25 =
35 Number of green stickers at first = 3 u - 348
Number of blue stickers at first = 2 u
Scenario 2 Fraction of the stickers that are blue
= 1 -
15=
45 Number of green stickers at first = 1 p
Number of blue stickers at first = 4 p - 258
3 u - 348 = 1 p --- (1)
2 u = 4 p - 258
2 u + 258 = 4 p --- (2)
(1)
x 4 12 u - 1392 = 4 p --- (3)
(3) = (2)
12 u - 1392 = 2 u + 258
12 u - 2 u = 1392 + 258
10 u = 1650
1 u = 1650 ÷ 10 = 165
Number of green stickers
= 3 u - 348
= 3 x 165 - 348
= 495 - 348
= 147
(b)
Number of blue stickers
= 2 u
= 2 x 165
= 330
Answer(s): (a) 147; (b) 330