Adam has some green stickers and blue stickers.
If 313 green stickers are added, 40% of the stickers will be blue stickers.
If 384 blue stickers are added, 25% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
3 u - 313 |
2 u |
1 p |
3 p - 384 |
Change |
+ 313 |
No change |
No change |
+ 384 |
After |
3 u |
2 u |
1 p |
3 p |
(a)
40% =
40100 =
25 25% =
25100 =
14 Scenario 1 Fraction of the stickers that are green
= 1 -
25 =
35 Number of green stickers at first = 3 u - 313
Number of blue stickers at first = 2 u
Scenario 2 Fraction of the stickers that are blue
= 1 -
14=
34 Number of green stickers at first = 1 p
Number of blue stickers at first = 3 p - 384
3 u - 313 = 1 p --- (1)
2 u = 3 p - 384
2 u + 384 = 3 p --- (2)
(1)
x 3 9 u - 939 = 3 p --- (3)
(3) = (2)
9 u - 939 = 2 u + 384
9 u - 2 u = 939 + 384
7 u = 1323
1 u = 1323 ÷ 7 = 189
Number of green stickers
= 3 u - 313
= 3 x 189 - 313
= 567 - 313
= 254
(b)
Number of blue stickers
= 2 u
= 2 x 189
= 378
Answer(s): (a) 254; (b) 378