Adam has some green stickers and red stickers.
If 181 green stickers are added, 40% of the stickers will be red stickers.
If 108 red stickers are added, 25% of the stickers will be green stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
3 u - 181 |
2 u |
1 p |
3 p - 108 |
Change |
+ 181 |
No change |
No change |
+ 108 |
After |
3 u |
2 u |
1 p |
3 p |
(a)
40% =
40100 =
25 25% =
25100 =
14 Scenario 1 Fraction of the stickers that are green
= 1 -
25 =
35 Number of green stickers at first = 3 u - 181
Number of red stickers at first = 2 u
Scenario 2 Fraction of the stickers that are red
= 1 -
14=
34 Number of green stickers at first = 1 p
Number of red stickers at first = 3 p - 108
3 u - 181 = 1 p --- (1)
2 u = 3 p - 108
2 u + 108 = 3 p --- (2)
(1)
x 3 9 u - 543 = 3 p --- (3)
(3) = (2)
9 u - 543 = 2 u + 108
9 u - 2 u = 543 + 108
7 u = 651
1 u = 651 ÷ 7 = 93
Number of green stickers
= 3 u - 181
= 3 x 93 - 181
= 279 - 181
= 98
(b)
Number of red stickers
= 2 u
= 2 x 93
= 186
Answer(s): (a) 98; (b) 186