Adam has some red stickers and green stickers.
If 316 red stickers are added, 30% of the stickers will be green stickers.
If 286 green stickers are added, 20% of the stickers will be red stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
7 u - 316 |
3 u |
1 p |
4 p - 286 |
Change |
+ 316 |
No change |
No change |
+ 286 |
After |
7 u |
3 u |
1 p |
4 p |
(a)
30% =
30100 =
310 20% =
20100 =
15 Scenario 1 Fraction of the stickers that are red
= 1 -
310 =
710 Number of red stickers at first = 7 u - 316
Number of green stickers at first = 3 u
Scenario 2 Fraction of the stickers that are green
= 1 -
15=
45 Number of red stickers at first = 1 p
Number of green stickers at first = 4 p - 286
7 u - 316 = 1 p --- (1)
3 u = 4 p - 286
3 u + 286 = 4 p --- (2)
(1)
x 4 28 u - 1264 = 4 p --- (3)
(3) = (2)
28 u - 1264 = 3 u + 286
28 u - 3 u = 1264 + 286
25 u = 1550
1 u = 1550 ÷ 25 = 62
Number of red stickers
= 7 u - 316
= 7 x 62 - 316
= 434 - 316
= 118
(b)
Number of green stickers
= 3 u
= 3 x 62
= 186
Answer(s): (a) 118; (b) 186