Adam has some blue stickers and green stickers.
If 277 blue stickers are added, 30% of the stickers will be green stickers.
If 147 green stickers are added, 10% of the stickers will be blue stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
7 u - 277 |
3 u |
1 p |
9 p - 147 |
Change |
+ 277 |
No change |
No change |
+ 147 |
After |
7 u |
3 u |
1 p |
9 p |
(a)
30% =
30100 =
310 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are blue
= 1 -
310 =
710 Number of blue stickers at first = 7 u - 277
Number of green stickers at first = 3 u
Scenario 2 Fraction of the stickers that are green
= 1 -
110=
910 Number of blue stickers at first = 1 p
Number of green stickers at first = 9 p - 147
7 u - 277 = 1 p --- (1)
3 u = 9 p - 147
3 u + 147 = 9 p --- (2)
(1)
x 9 63 u - 2493 = 9 p --- (3)
(3) = (2)
63 u - 2493 = 3 u + 147
63 u - 3 u = 2493 + 147
60 u = 2640
1 u = 2640 ÷ 60 = 44
Number of blue stickers
= 7 u - 277
= 7 x 44 - 277
= 308 - 277
= 31
(b)
Number of green stickers
= 3 u
= 3 x 44
= 132
Answer(s): (a) 31; (b) 132