Adam has some green stickers and red stickers.
If 329 green stickers are added, 40% of the stickers will be red stickers.
If 392 red stickers are added, 25% of the stickers will be green stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
3 u - 329 |
2 u |
1 p |
3 p - 392 |
Change |
+ 329 |
No change |
No change |
+ 392 |
After |
3 u |
2 u |
1 p |
3 p |
(a)
40% =
40100 =
25 25% =
25100 =
14 Scenario 1 Fraction of the stickers that are green
= 1 -
25 =
35 Number of green stickers at first = 3 u - 329
Number of red stickers at first = 2 u
Scenario 2 Fraction of the stickers that are red
= 1 -
14=
34 Number of green stickers at first = 1 p
Number of red stickers at first = 3 p - 392
3 u - 329 = 1 p --- (1)
2 u = 3 p - 392
2 u + 392 = 3 p --- (2)
(1)
x 3 9 u - 987 = 3 p --- (3)
(3) = (2)
9 u - 987 = 2 u + 392
9 u - 2 u = 987 + 392
7 u = 1379
1 u = 1379 ÷ 7 = 197
Number of green stickers
= 3 u - 329
= 3 x 197 - 329
= 591 - 329
= 262
(b)
Number of red stickers
= 2 u
= 2 x 197
= 394
Answer(s): (a) 262; (b) 394