Adam has some green stickers and blue stickers.
If 276 green stickers are added, 40% of the stickers will be blue stickers.
If 291 blue stickers are added, 10% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
3 u - 276 |
2 u |
1 p |
9 p - 291 |
Change |
+ 276 |
No change |
No change |
+ 291 |
After |
3 u |
2 u |
1 p |
9 p |
(a)
40% =
40100 =
25 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are green
= 1 -
25 =
35 Number of green stickers at first = 3 u - 276
Number of blue stickers at first = 2 u
Scenario 2 Fraction of the stickers that are blue
= 1 -
110=
910 Number of green stickers at first = 1 p
Number of blue stickers at first = 9 p - 291
3 u - 276 = 1 p --- (1)
2 u = 9 p - 291
2 u + 291 = 9 p --- (2)
(1)
x 9 27 u - 2484 = 9 p --- (3)
(3) = (2)
27 u - 2484 = 2 u + 291
27 u - 2 u = 2484 + 291
25 u = 2775
1 u = 2775 ÷ 25 = 111
Number of green stickers
= 3 u - 276
= 3 x 111 - 276
= 333 - 276
= 57
(b)
Number of blue stickers
= 2 u
= 2 x 111
= 222
Answer(s): (a) 57; (b) 222