Adam has some green stickers and blue stickers.
If 183 green stickers are added, 40% of the stickers will be blue stickers.
If 278 blue stickers are added, 20% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
3 u - 183 |
2 u |
1 p |
4 p - 278 |
Change |
+ 183 |
No change |
No change |
+ 278 |
After |
3 u |
2 u |
1 p |
4 p |
(a)
40% =
40100 =
25 20% =
20100 =
15 Scenario 1 Fraction of the stickers that are green
= 1 -
25 =
35 Number of green stickers at first = 3 u - 183
Number of blue stickers at first = 2 u
Scenario 2 Fraction of the stickers that are blue
= 1 -
15=
45 Number of green stickers at first = 1 p
Number of blue stickers at first = 4 p - 278
3 u - 183 = 1 p --- (1)
2 u = 4 p - 278
2 u + 278 = 4 p --- (2)
(1)
x 4 12 u - 732 = 4 p --- (3)
(3) = (2)
12 u - 732 = 2 u + 278
12 u - 2 u = 732 + 278
10 u = 1010
1 u = 1010 ÷ 10 = 101
Number of green stickers
= 3 u - 183
= 3 x 101 - 183
= 303 - 183
= 120
(b)
Number of blue stickers
= 2 u
= 2 x 101
= 202
Answer(s): (a) 120; (b) 202