Adam has some green stickers and blue stickers.
If 259 green stickers are added, 40% of the stickers will be blue stickers.
If 203 blue stickers are added, 25% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
3 u - 259 |
2 u |
1 p |
3 p - 203 |
Change |
+ 259 |
No change |
No change |
+ 203 |
After |
3 u |
2 u |
1 p |
3 p |
(a)
40% =
40100 =
25 25% =
25100 =
14 Scenario 1 Fraction of the stickers that are green
= 1 -
25 =
35 Number of green stickers at first = 3 u - 259
Number of blue stickers at first = 2 u
Scenario 2 Fraction of the stickers that are blue
= 1 -
14=
34 Number of green stickers at first = 1 p
Number of blue stickers at first = 3 p - 203
3 u - 259 = 1 p --- (1)
2 u = 3 p - 203
2 u + 203 = 3 p --- (2)
(1)
x 3 9 u - 777 = 3 p --- (3)
(3) = (2)
9 u - 777 = 2 u + 203
9 u - 2 u = 777 + 203
7 u = 980
1 u = 980 ÷ 7 = 140
Number of green stickers
= 3 u - 259
= 3 x 140 - 259
= 420 - 259
= 161
(b)
Number of blue stickers
= 2 u
= 2 x 140
= 280
Answer(s): (a) 161; (b) 280