Adam has some red stickers and green stickers.
If 298 red stickers are removed, 25% of the stickers will be red stickers.
If 380 green stickers are removed, 10% of the stickers will be green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 298 |
3 u |
9 p |
1 p + 380 |
Change |
- 298 |
No change |
No change |
- 380 |
After |
1 u |
3 u |
9 p |
1 p |
(a)
25% =
25100 =
14 10% =
10100 =
110 Scenario 1Fraction of the stickers that are green
= 1 -
14 =
34 Scenario 2Fraction of the stickers that are red
= 1 -
110 =
9101 u + 298 = 9 p --- (1)
3 u = 1 p + 380 --- (2)
From (1)
1 u = 9 p - 298 --- (3)
(3)
x 33 u = 27 p - 894 --- (4)
(4) = (2)
27 p - 894 = 1 p + 380
27 p - 1 p = 894 + 380
26 p = 1274
1 p = 1274 ÷ 26 = 49Number of red stickers = 9 p
= 9 x 49= 441 (b) Number of green stickers = 1 p + 380 = 49 + 380 = 429 Answer(s): (a) 441; (b) 429