Adam has some red stickers and green stickers.
If 117 red stickers are removed, 25% of the stickers will be red stickers.
If 221 green stickers are removed, 10% of the stickers will be green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 117 |
3 u |
9 p |
1 p + 221 |
Change |
- 117 |
No change |
No change |
- 221 |
After |
1 u |
3 u |
9 p |
1 p |
(a)
25% =
25100 =
14 10% =
10100 =
110 Scenario 1Fraction of the stickers that are green
= 1 -
14 =
34 Scenario 2Fraction of the stickers that are red
= 1 -
110 =
9101 u + 117 = 9 p --- (1)
3 u = 1 p + 221 --- (2)
From (1)
1 u = 9 p - 117 --- (3)
(3)
x 33 u = 27 p - 351 --- (4)
(4) = (2)
27 p - 351 = 1 p + 221
27 p - 1 p = 351 + 221
26 p = 572
1 p = 572 ÷ 26 = 22Number of red stickers = 9 p
= 9 x 22= 198 (b) Number of green stickers = 1 p + 221 = 22 + 221 = 243 Answer(s): (a) 198; (b) 243