Adam has some green stickers and blue stickers.
If 167 green stickers are removed, 25% of the stickers will be green stickers.
If 148 blue stickers are removed, 20% of the stickers will be blue stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 167 |
3 u |
4 p |
1 p + 148 |
Change |
- 167 |
No change |
No change |
- 148 |
After |
1 u |
3 u |
4 p |
1 p |
(a)
25% =
25100 =
14 20% =
20100 =
15 Scenario 1Fraction of the stickers that are blue
= 1 -
14 =
34 Scenario 2Fraction of the stickers that are green
= 1 -
15 =
451 u + 167 = 4 p --- (1)
3 u = 1 p + 148 --- (2)
From (1)
1 u = 4 p - 167 --- (3)
(3)
x 33 u = 12 p - 501 --- (4)
(4) = (2)
12 p - 501 = 1 p + 148
12 p - 1 p = 501 + 148
11 p = 649
1 p = 649 ÷ 11 = 59Number of green stickers = 4 p
= 4 x 59= 236 (b) Number of blue stickers = 1 p + 148 = 59 + 148 = 207 Answer(s): (a) 236; (b) 207