Adam has some blue stickers and green stickers.
If 179 blue stickers are removed, 25% of the stickers will be blue stickers.
If 139 green stickers are removed, 10% of the stickers will be green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 179 |
3 u |
9 p |
1 p + 139 |
Change |
- 179 |
No change |
No change |
- 139 |
After |
1 u |
3 u |
9 p |
1 p |
(a)
25% =
25100 =
14 10% =
10100 =
110 Scenario 1Fraction of the stickers that are green
= 1 -
14 =
34 Scenario 2Fraction of the stickers that are blue
= 1 -
110 =
9101 u + 179 = 9 p --- (1)
3 u = 1 p + 139 --- (2)
From (1)
1 u = 9 p - 179 --- (3)
(3)
x 33 u = 27 p - 537 --- (4)
(4) = (2)
27 p - 537 = 1 p + 139
27 p - 1 p = 537 + 139
26 p = 676
1 p = 676 ÷ 26 = 26Number of blue stickers = 9 p
= 9 x 26= 234 (b) Number of green stickers = 1 p + 139 = 26 + 139 = 165 Answer(s): (a) 234; (b) 165