Adam has some green stickers and blue stickers.
If 211 green stickers are removed, 20% of the stickers will be green stickers.
If 101 blue stickers are removed, 10% of the stickers will be blue stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 211 |
4 u |
9 p |
1 p + 101 |
Change |
- 211 |
No change |
No change |
- 101 |
After |
1 u |
4 u |
9 p |
1 p |
(a)
20% =
20100 =
15 10% =
10100 =
110 Scenario 1Fraction of the stickers that are blue
= 1 -
15 =
45 Scenario 2Fraction of the stickers that are green
= 1 -
110 =
9101 u + 211 = 9 p --- (1)
4 u = 1 p + 101 --- (2)
From (1)
1 u = 9 p - 211 --- (3)
(3)
x 44 u = 36 p - 844 --- (4)
(4) = (2)
36 p - 844 = 1 p + 101
36 p - 1 p = 844 + 101
35 p = 945
1 p = 945 ÷ 35 = 27Number of green stickers = 9 p
= 9 x 27= 243 (b) Number of blue stickers = 1 p + 101 = 27 + 101 = 128 Answer(s): (a) 243; (b) 128