Adam has some blue stickers and green stickers.
If 140 blue stickers are removed, 25% of the stickers will be blue stickers.
If 282 green stickers are removed, 10% of the stickers will be green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 140 |
3 u |
9 p |
1 p + 282 |
Change |
- 140 |
No change |
No change |
- 282 |
After |
1 u |
3 u |
9 p |
1 p |
(a)
25% =
25100 =
14 10% =
10100 =
110 Scenario 1Fraction of the stickers that are green
= 1 -
14 =
34 Scenario 2Fraction of the stickers that are blue
= 1 -
110 =
9101 u + 140 = 9 p --- (1)
3 u = 1 p + 282 --- (2)
From (1)
1 u = 9 p - 140 --- (3)
(3)
x 33 u = 27 p - 420 --- (4)
(4) = (2)
27 p - 420 = 1 p + 282
27 p - 1 p = 420 + 282
26 p = 702
1 p = 702 ÷ 26 = 27Number of blue stickers = 9 p
= 9 x 27= 243 (b) Number of green stickers = 1 p + 282 = 27 + 282 = 309 Answer(s): (a) 243; (b) 309