Adam has some blue stickers and green stickers.
If 113 blue stickers are removed, 20% of the stickers will be blue stickers.
If 353 green stickers are removed, 10% of the stickers will be green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 113 |
4 u |
9 p |
1 p + 353 |
Change |
- 113 |
No change |
No change |
- 353 |
After |
1 u |
4 u |
9 p |
1 p |
(a)
20% =
20100 =
15 10% =
10100 =
110 Scenario 1Fraction of the stickers that are green
= 1 -
15 =
45 Scenario 2Fraction of the stickers that are blue
= 1 -
110 =
9101 u + 113 = 9 p --- (1)
4 u = 1 p + 353 --- (2)
From (1)
1 u = 9 p - 113 --- (3)
(3)
x 44 u = 36 p - 452 --- (4)
(4) = (2)
36 p - 452 = 1 p + 353
36 p - 1 p = 452 + 353
35 p = 805
1 p = 805 ÷ 35 = 23Number of blue stickers = 9 p
= 9 x 23= 207 (b) Number of green stickers = 1 p + 353 = 23 + 353 = 376 Answer(s): (a) 207; (b) 376