Adam has some red stickers and green stickers.
If 292 red stickers are removed, 25% of the stickers will be red stickers.
If 257 green stickers are removed, 20% of the stickers will be green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 292 |
3 u |
4 p |
1 p + 257 |
Change |
- 292 |
No change |
No change |
- 257 |
After |
1 u |
3 u |
4 p |
1 p |
(a)
25% =
25100 =
14 20% =
20100 =
15 Scenario 1Fraction of the stickers that are green
= 1 -
14 =
34 Scenario 2Fraction of the stickers that are red
= 1 -
15 =
451 u + 292 = 4 p --- (1)
3 u = 1 p + 257 --- (2)
From (1)
1 u = 4 p - 292 --- (3)
(3)
x 33 u = 12 p - 876 --- (4)
(4) = (2)
12 p - 876 = 1 p + 257
12 p - 1 p = 876 + 257
11 p = 1133
1 p = 1133 ÷ 11 = 103Number of red stickers = 4 p
= 4 x 103= 412 (b) Number of green stickers = 1 p + 257 = 103 + 257 = 360 Answer(s): (a) 412; (b) 360